20x/(4x-1)+2/x=5

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Solution for 20x/(4x-1)+2/x=5 equation: 



20x/(4x-1)+2/x=5

We move all terms to the left:

20x/(4x-1)+2/x-(5)=0



Domain of the equation: (4x-1)!=0

We move all terms containing x to the left, all other terms to the right

4x!=1

x!=1/4

x!=1/4

x∈R





Domain of the equation: x!=0

x∈R



We calculate fractions


20x^2/(4x^2-1x)+(8x-2)/(4x^2-1x)-5=0

We multiply all the terms by the denominator


20x^2+(8x-2)-5*(4x^2-1x)=0

We multiply parentheses

20x^2-20x^2+(8x-2)+5x=0

We get rid of parentheses

20x^2-20x^2+8x+5x-2=0

We add all the numbers together, and all the variables

13x-2=0

We move all terms containing x to the left, all other terms to the right

13x=2

x=2/13

x=2/13

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