20x2(1-x)=128

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Solution for 20x2(1-x)=128 equation: 



20x^2(1-x)=128

We move all terms to the left:

20x^2(1-x)-(128)=0

We add all the numbers together, and all the variables

20x^2(-1x+1)-128=0

We move all terms containing x to the left, all other terms to the right

20x^2(-1x+1)=128

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