20x2-157x+222=0

Solution for 20x2-157x+222=0 equation:

20x^2-157x+222=0

a = 20; b = -157; c = +222;
Δ = b2-4ac
Δ = -1572-4·20·222
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6889}=83$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-157)-83}{2*20}=\frac{74}{40}
=1+17/20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-157)+83}{2*20}=\frac{240}{40}
=6
$