20x2-27x+9=0

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Solution for 20x2-27x+9=0 equation:



20x^2-27x+9=0
a = 20; b = -27; c = +9;
Δ = b2-4ac
Δ = -272-4·20·9
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3}{2*20}=\frac{24}{40} =3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3}{2*20}=\frac{30}{40} =3/4 $

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