20x2-71x+63=0

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Solution for 20x2-71x+63=0 equation:



20x^2-71x+63=0
a = 20; b = -71; c = +63;
Δ = b2-4ac
Δ = -712-4·20·63
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-71)-1}{2*20}=\frac{70}{40} =1+3/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-71)+1}{2*20}=\frac{72}{40} =1+4/5 $

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