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20x=x2-300
We move all terms to the left:
20x-(x2-300)=0
We add all the numbers together, and all the variables
-(+x^2-300)+20x=0
We get rid of parentheses
-x^2+20x+300=0
We add all the numbers together, and all the variables
-1x^2+20x+300=0
a = -1; b = 20; c = +300;
Δ = b2-4ac
Δ = 202-4·(-1)·300
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-40}{2*-1}=\frac{-60}{-2} =+30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+40}{2*-1}=\frac{20}{-2} =-10 $
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