20xxy/36xz

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Solution for 20xxy/36xz equation: 


1;2;2;3;2;-3

1;3;2;3;2;-3

(4*x^2+10*x+1)/((x^2-(3*x)-4)^2)

3;5;1;3;0;2

((2*x)/35)/5 = 0

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