20y+(8y-15)=3(4y-5)

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Solution for 20y+(8y-15)=3(4y-5) equation: 



20y+(8y-15)=3(4y-5)

We move all terms to the left:

20y+(8y-15)-(3(4y-5))=0

We get rid of parentheses

20y+8y-(3(4y-5))-15=0



We calculate terms in parentheses: -(3(4y-5)), so:

3(4y-5)

We multiply parentheses

12y-15

Back to the equation:

-(12y-15)



We add all the numbers together, and all the variables

28y-(12y-15)-15=0

We get rid of parentheses

28y-12y+15-15=0

We add all the numbers together, and all the variables

16y=0

y=0/16

y=0

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