20y+12-y=16y-16

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Solution for 20y+12-y=16y-16 equation: 



20y+12-y=16y-16

We move all terms to the left:

20y+12-y-(16y-16)=0

We add all the numbers together, and all the variables

19y-(16y-16)+12=0

We get rid of parentheses

19y-16y+16+12=0

We add all the numbers together, and all the variables

3y+28=0

We move all terms containing y to the left, all other terms to the right

3y=-28

y=-28/3

y=-9+1/3

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