20y+6=4(3y+1)

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Solution for 20y+6=4(3y+1) equation: 



20y+6=4(3y+1)

We move all terms to the left:

20y+6-(4(3y+1))=0



We calculate terms in parentheses: -(4(3y+1)), so:

4(3y+1)

We multiply parentheses

12y+4

Back to the equation:

-(12y+4)



We get rid of parentheses

20y-12y-4+6=0

We add all the numbers together, and all the variables

8y+2=0

We move all terms containing y to the left, all other terms to the right

8y=-2

y=-2/8

y=-1/4

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