20y-(4y+9)=8(2y-3)+15

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Solution for 20y-(4y+9)=8(2y-3)+15 equation:


Simplifying
20y + -1(4y + 9) = 8(2y + -3) + 15

Reorder the terms:
20y + -1(9 + 4y) = 8(2y + -3) + 15
20y + (9 * -1 + 4y * -1) = 8(2y + -3) + 15
20y + (-9 + -4y) = 8(2y + -3) + 15

Reorder the terms:
-9 + 20y + -4y = 8(2y + -3) + 15

Combine like terms: 20y + -4y = 16y
-9 + 16y = 8(2y + -3) + 15

Reorder the terms:
-9 + 16y = 8(-3 + 2y) + 15
-9 + 16y = (-3 * 8 + 2y * 8) + 15
-9 + 16y = (-24 + 16y) + 15

Reorder the terms:
-9 + 16y = -24 + 15 + 16y

Combine like terms: -24 + 15 = -9
-9 + 16y = -9 + 16y

Add '9' to each side of the equation.
-9 + 9 + 16y = -9 + 9 + 16y

Combine like terms: -9 + 9 = 0
0 + 16y = -9 + 9 + 16y
16y = -9 + 9 + 16y

Combine like terms: -9 + 9 = 0
16y = 0 + 16y
16y = 16y

Add '-16y' to each side of the equation.
16y + -16y = 16y + -16y

Combine like terms: 16y + -16y = 0
0 = 16y + -16y

Combine like terms: 16y + -16y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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