20y-12/4y=4

Solution for 20y-12/4y=4 equation:

20y-12/4y=4

We move all terms to the left:

20y-12/4y-(4)=0


Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R


We multiply all the terms by the denominator


20y*4y-4*4y-12=0

Wy multiply elements

80y^2-16y-12=0

a = 80; b = -16; c = -12;
Δ = b2-4ac
Δ = -162-4·80·(-12)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-64}{2*80}=\frac{-48}{160}
=-3/10
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+64}{2*80}=\frac{80}{160}
=1/2
$