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20y-12/4y=4
We move all terms to the left:
20y-12/4y-(4)=0
Domain of the equation: 4y!=0We multiply all the terms by the denominator
y!=0/4
y!=0
y∈R
20y*4y-4*4y-12=0
Wy multiply elements
80y^2-16y-12=0
a = 80; b = -16; c = -12;
Δ = b2-4ac
Δ = -162-4·80·(-12)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-64}{2*80}=\frac{-48}{160} =-3/10 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+64}{2*80}=\frac{80}{160} =1/2 $
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