20y-18=5(3y+4)+2

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Solution for 20y-18=5(3y+4)+2 equation: 



20y-18=5(3y+4)+2

We move all terms to the left:

20y-18-(5(3y+4)+2)=0



We calculate terms in parentheses: -(5(3y+4)+2), so:

5(3y+4)+2

We multiply parentheses

15y+20+2

We add all the numbers together, and all the variables

15y+22

Back to the equation:

-(15y+22)



We get rid of parentheses

20y-15y-22-18=0

We add all the numbers together, and all the variables

5y-40=0

We move all terms containing y to the left, all other terms to the right

5y=40

y=40/5

y=8

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