20y-8=4(5y-2)

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Solution for 20y-8=4(5y-2) equation: 



20y-8=4(5y-2)

We move all terms to the left:

20y-8-(4(5y-2))=0



We calculate terms in parentheses: -(4(5y-2)), so:

4(5y-2)

We multiply parentheses

20y-8

Back to the equation:

-(20y-8)



We get rid of parentheses

20y-20y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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