20y3/5=2y

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Solution for 20y3/5=2y equation: 


y in (-oo:+oo)

(20*y^3)/5 = 2*y // - 2*y

(20*y^3)/5-(2*y) = 0

(20*y^3)/5-2*y = 0

4*y^3-2*y = 0

2*y*(2*y^2-1) = 0

2*y^2 = 1 // : 2

y^2 = 1/2

y^2 = 1/2 // ^ 1/2

abs(y) = (1/2)^(1/2)

y = (1/2)^(1/2) or y = -(1/2)^(1/2)

2*y = 0

2*y = 0 // : 2

y = 0

y in { (1/2)^(1/2), -(1/2)^(1/2), 0 }

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