20y=12y2

Solution for 20y=12y2 equation:

20y=12y^2

We move all terms to the left:

20y-(12y^2)=0

determiningTheFunctionDomain
-12y^2+20y=0

a = -12; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-12)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-12}=\frac{-40}{-24}
=1+2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-12}=\frac{0}{-24}
=0
$