20z-3(-2z-4)=12+16z+10z

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Solution for 20z-3(-2z-4)=12+16z+10z equation: 


Simplifying
20z + -3(-2z + -4) = 12 + 16z + 10z

Reorder the terms:
20z + -3(-4 + -2z) = 12 + 16z + 10z
20z + (-4 * -3 + -2z * -3) = 12 + 16z + 10z
20z + (12 + 6z) = 12 + 16z + 10z

Reorder the terms:
12 + 20z + 6z = 12 + 16z + 10z

Combine like terms: 20z + 6z = 26z
12 + 26z = 12 + 16z + 10z

Combine like terms: 16z + 10z = 26z
12 + 26z = 12 + 26z

Add '-12' to each side of the equation.
12 + -12 + 26z = 12 + -12 + 26z

Combine like terms: 12 + -12 = 0
0 + 26z = 12 + -12 + 26z
26z = 12 + -12 + 26z

Combine like terms: 12 + -12 = 0
26z = 0 + 26z
26z = 26z

Add '-26z' to each side of the equation.
26z + -26z = 26z + -26z

Combine like terms: 26z + -26z = 0
0 = 26z + -26z

Combine like terms: 26z + -26z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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