21(2-c)+12c=44

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Solution for 21(2-c)+12c=44 equation: 



21(2-c)+12c=44

We move all terms to the left:

21(2-c)+12c-(44)=0

We add all the numbers together, and all the variables

21(-1c+2)+12c-44=0

We add all the numbers together, and all the variables

12c+21(-1c+2)-44=0

We multiply parentheses

12c-21c+42-44=0

We add all the numbers together, and all the variables

-9c-2=0

We move all terms containing c to the left, all other terms to the right

-9c=2

c=2/-9

c=-2/9

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