21(3x-7)=28(x+11)

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Solution for 21(3x-7)=28(x+11) equation: 



21(3x-7)=28(x+11)

We move all terms to the left:

21(3x-7)-(28(x+11))=0

We multiply parentheses

63x-(28(x+11))-147=0



We calculate terms in parentheses: -(28(x+11)), so:

28(x+11)

We multiply parentheses

28x+308

Back to the equation:

-(28x+308)



We get rid of parentheses

63x-28x-308-147=0

We add all the numbers together, and all the variables

35x-455=0

We move all terms containing x to the left, all other terms to the right

35x=455

x=455/35

x=13

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