21(b-1)+6=3(7b-5)

Solution for 21(b-1)+6=3(7b-5) equation:

Simplifying
21(b + -1) + 6 = 3(7b + -5)

Reorder the terms:
21(-1 + b) + 6 = 3(7b + -5)
(-1 * 21 + b * 21) + 6 = 3(7b + -5)
(-21 + 21b) + 6 = 3(7b + -5)

Reorder the terms:
-21 + 6 + 21b = 3(7b + -5)

Combine like terms: -21 + 6 = -15
-15 + 21b = 3(7b + -5)

Reorder the terms:
-15 + 21b = 3(-5 + 7b)
-15 + 21b = (-5 * 3 + 7b * 3)
-15 + 21b = (-15 + 21b)

Add '15' to each side of the equation.
-15 + 15 + 21b = -15 + 15 + 21b

Combine like terms: -15 + 15 = 0
0 + 21b = -15 + 15 + 21b
21b = -15 + 15 + 21b

Combine like terms: -15 + 15 = 0
21b = 0 + 21b
21b = 21b

Add '-21b' to each side of the equation.
21b + -21b = 21b + -21b

Combine like terms: 21b + -21b = 0
0 = 21b + -21b

Combine like terms: 21b + -21b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.