21(b-1)+9=3(7b-4)

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Solution for 21(b-1)+9=3(7b-4) equation:


Simplifying
21(b + -1) + 9 = 3(7b + -4)

Reorder the terms:
21(-1 + b) + 9 = 3(7b + -4)
(-1 * 21 + b * 21) + 9 = 3(7b + -4)
(-21 + 21b) + 9 = 3(7b + -4)

Reorder the terms:
-21 + 9 + 21b = 3(7b + -4)

Combine like terms: -21 + 9 = -12
-12 + 21b = 3(7b + -4)

Reorder the terms:
-12 + 21b = 3(-4 + 7b)
-12 + 21b = (-4 * 3 + 7b * 3)
-12 + 21b = (-12 + 21b)

Add '12' to each side of the equation.
-12 + 12 + 21b = -12 + 12 + 21b

Combine like terms: -12 + 12 = 0
0 + 21b = -12 + 12 + 21b
21b = -12 + 12 + 21b

Combine like terms: -12 + 12 = 0
21b = 0 + 21b
21b = 21b

Add '-21b' to each side of the equation.
21b + -21b = 21b + -21b

Combine like terms: 21b + -21b = 0
0 = 21b + -21b

Combine like terms: 21b + -21b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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