21(e+5)-42=7(3e+9)

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Solution for 21(e+5)-42=7(3e+9) equation: 



21(e+5)-42=7(3e+9)

We move all terms to the left:

21(e+5)-42-(7(3e+9))=0

We multiply parentheses

21e-(7(3e+9))+105-42=0



We calculate terms in parentheses: -(7(3e+9)), so:

7(3e+9)

We multiply parentheses

21e+63

Back to the equation:

-(21e+63)



We add all the numbers together, and all the variables

21e-(21e+63)+63=0

We get rid of parentheses

21e-21e-63+63=0

We add all the numbers together, and all the variables

=0

e=0/1

e=0

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