21(x+1)=2(4x+5)

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Solution for 21(x+1)=2(4x+5) equation: 



21(x+1)=2(4x+5)

We move all terms to the left:

21(x+1)-(2(4x+5))=0

We multiply parentheses

21x-(2(4x+5))+21=0



We calculate terms in parentheses: -(2(4x+5)), so:

2(4x+5)

We multiply parentheses

8x+10

Back to the equation:

-(8x+10)



We get rid of parentheses

21x-8x-10+21=0

We add all the numbers together, and all the variables

13x+11=0

We move all terms containing x to the left, all other terms to the right

13x=-11

x=-11/13

x=-11/13

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