21(x+2)+12x=108

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Solution for 21(x+2)+12x=108 equation:



21(x+2)+12x=108
We move all terms to the left:
21(x+2)+12x-(108)=0
We add all the numbers together, and all the variables
12x+21(x+2)-108=0
We multiply parentheses
12x+21x+42-108=0
We add all the numbers together, and all the variables
33x-66=0
We move all terms containing x to the left, all other terms to the right
33x=66
x=66/33
x=2

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