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21(x+3)=15(x+5)
We move all terms to the left:
21(x+3)-(15(x+5))=0
We multiply parentheses
21x-(15(x+5))+63=0
We calculate terms in parentheses: -(15(x+5)), so:We get rid of parentheses
15(x+5)
We multiply parentheses
15x+75
Back to the equation:
-(15x+75)
21x-15x-75+63=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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