21(x+5)=147

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Solution for 21(x+5)=147 equation: 



21(x+5)=147

We move all terms to the left:

21(x+5)-(147)=0

We multiply parentheses

21x+105-147=0

We add all the numbers together, and all the variables

21x-42=0

We move all terms containing x to the left, all other terms to the right

21x=42

x=42/21

x=2

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