21+(z-3)=6z+5

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Solution for 21+(z-3)=6z+5 equation: 



21+(z-3)=6z+5

We move all terms to the left:

21+(z-3)-(6z+5)=0

We get rid of parentheses

z-6z-3-5+21=0

We add all the numbers together, and all the variables

-5z+13=0

We move all terms containing z to the left, all other terms to the right

-5z=-13

z=-13/-5

z=2+3/5

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