21+3(b+5)=48

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Solution for 21+3(b+5)=48 equation: 



21+3(b+5)=48

We move all terms to the left:

21+3(b+5)-(48)=0

We add all the numbers together, and all the variables

3(b+5)-27=0

We multiply parentheses

3b+15-27=0

We add all the numbers together, and all the variables

3b-12=0

We move all terms containing b to the left, all other terms to the right

3b=12

b=12/3

b=4

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