21+3(x-4)=4(x+15)

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Solution for 21+3(x-4)=4(x+15) equation: 



21+3(x-4)=4(x+15)

We move all terms to the left:

21+3(x-4)-(4(x+15))=0

We multiply parentheses

3x-(4(x+15))-12+21=0



We calculate terms in parentheses: -(4(x+15)), so:

4(x+15)

We multiply parentheses

4x+60

Back to the equation:

-(4x+60)



We add all the numbers together, and all the variables

3x-(4x+60)+9=0

We get rid of parentheses

3x-4x-60+9=0

We add all the numbers together, and all the variables

-1x-51=0

We move all terms containing x to the left, all other terms to the right

-x=51

x=51/-1

x=-51

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