21+3b=-8b-5(b-1)

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Solution for 21+3b=-8b-5(b-1) equation: 



21+3b=-8b-5(b-1)

We move all terms to the left:

21+3b-(-8b-5(b-1))=0



We calculate terms in parentheses: -(-8b-5(b-1)), so:

-8b-5(b-1)

We multiply parentheses

-8b-5b+5

We add all the numbers together, and all the variables

-13b+5

Back to the equation:

-(-13b+5)



We get rid of parentheses

3b+13b-5+21=0

We add all the numbers together, and all the variables

16b+16=0

We move all terms containing b to the left, all other terms to the right

16b=-16

b=-16/16

b=-1

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