21+3r=4(r+6)

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Solution for 21+3r=4(r+6) equation: 



21+3r=4(r+6)

We move all terms to the left:

21+3r-(4(r+6))=0



We calculate terms in parentheses: -(4(r+6)), so:

4(r+6)

We multiply parentheses

4r+24

Back to the equation:

-(4r+24)



We get rid of parentheses

3r-4r-24+21=0

We add all the numbers together, and all the variables

-1r-3=0

We move all terms containing r to the left, all other terms to the right

-r=3

r=3/-1

r=-3

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