21+7x=2(x-3)+48-4(3-x)

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Solution for 21+7x=2(x-3)+48-4(3-x) equation: 



21+7x=2(x-3)+48-4(3-x)

We move all terms to the left:

21+7x-(2(x-3)+48-4(3-x))=0

We add all the numbers together, and all the variables

7x-(2(x-3)+48-4(-1x+3))+21=0



We calculate terms in parentheses: -(2(x-3)+48-4(-1x+3)), so:

2(x-3)+48-4(-1x+3)

determiningTheFunctionDomain
2(x-3)-4(-1x+3)+48

We multiply parentheses

2x+4x-6-12+48

We add all the numbers together, and all the variables

6x+30

Back to the equation:

-(6x+30)



We get rid of parentheses

7x-6x-30+21=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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