21-(n-4)=5(n+4)

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Solution for 21-(n-4)=5(n+4) equation:


Simplifying
21 + -1(n + -4) = 5(n + 4)

Reorder the terms:
21 + -1(-4 + n) = 5(n + 4)
21 + (-4 * -1 + n * -1) = 5(n + 4)
21 + (4 + -1n) = 5(n + 4)

Combine like terms: 21 + 4 = 25
25 + -1n = 5(n + 4)

Reorder the terms:
25 + -1n = 5(4 + n)
25 + -1n = (4 * 5 + n * 5)
25 + -1n = (20 + 5n)

Solving
25 + -1n = 20 + 5n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-5n' to each side of the equation.
25 + -1n + -5n = 20 + 5n + -5n

Combine like terms: -1n + -5n = -6n
25 + -6n = 20 + 5n + -5n

Combine like terms: 5n + -5n = 0
25 + -6n = 20 + 0
25 + -6n = 20

Add '-25' to each side of the equation.
25 + -25 + -6n = 20 + -25

Combine like terms: 25 + -25 = 0
0 + -6n = 20 + -25
-6n = 20 + -25

Combine like terms: 20 + -25 = -5
-6n = -5

Divide each side by '-6'.
n = 0.8333333333

Simplifying
n = 0.8333333333

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