21-4(-x)=2(-x)+3

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Solution for 21-4(-x)=2(-x)+3 equation: 



21-4(-x)=2(-x)+3

We move all terms to the left:

21-4(-x)-(2(-x)+3)=0

We add all the numbers together, and all the variables

-4(-1x)-(2(-1x)+3)+21=0

We multiply parentheses

4x-(2(-1x)+3)+21=0



We calculate terms in parentheses: -(2(-1x)+3), so:

2(-1x)+3

We multiply parentheses

-2x+3

Back to the equation:

-(-2x+3)



We get rid of parentheses

4x+2x-3+21=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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