21-47=3(x-4)-5

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Solution for 21-47=3(x-4)-5 equation: 



21-47=3(x-4)-5

We move all terms to the left:

21-47-(3(x-4)-5)=0

We add all the numbers together, and all the variables

-(3(x-4)-5)-26=0



We calculate terms in parentheses: -(3(x-4)-5), so:

3(x-4)-5

We multiply parentheses

3x-12-5

We add all the numbers together, and all the variables

3x-17

Back to the equation:

-(3x-17)



We get rid of parentheses

-3x+17-26=0

We add all the numbers together, and all the variables

-3x-9=0

We move all terms containing x to the left, all other terms to the right

-3x=9

x=9/-3

x=-3

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