21-48=3(x-3)-6

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Solution for 21-48=3(x-3)-6 equation: 



21-48=3(x-3)-6

We move all terms to the left:

21-48-(3(x-3)-6)=0

We add all the numbers together, and all the variables

-(3(x-3)-6)-27=0



We calculate terms in parentheses: -(3(x-3)-6), so:

3(x-3)-6

We multiply parentheses

3x-9-6

We add all the numbers together, and all the variables

3x-15

Back to the equation:

-(3x-15)



We get rid of parentheses

-3x+15-27=0

We add all the numbers together, and all the variables

-3x-12=0

We move all terms containing x to the left, all other terms to the right

-3x=12

x=12/-3

x=-4

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