21-4x=2(3x+12)

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Solution for 21-4x=2(3x+12) equation: 



21-4x=2(3x+12)

We move all terms to the left:

21-4x-(2(3x+12))=0



We calculate terms in parentheses: -(2(3x+12)), so:

2(3x+12)

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We get rid of parentheses

-4x-6x-24+21=0

We add all the numbers together, and all the variables

-10x-3=0

We move all terms containing x to the left, all other terms to the right

-10x=3

x=3/-10

x=-3/10

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