21-7(1-x)=6(3x-5)

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Solution for 21-7(1-x)=6(3x-5) equation: 



21-7(1-x)=6(3x-5)

We move all terms to the left:

21-7(1-x)-(6(3x-5))=0

We add all the numbers together, and all the variables

-7(-1x+1)-(6(3x-5))+21=0

We multiply parentheses

7x-(6(3x-5))-7+21=0



We calculate terms in parentheses: -(6(3x-5)), so:

6(3x-5)

We multiply parentheses

18x-30

Back to the equation:

-(18x-30)



We add all the numbers together, and all the variables

7x-(18x-30)+14=0

We get rid of parentheses

7x-18x+30+14=0

We add all the numbers together, and all the variables

-11x+44=0

We move all terms containing x to the left, all other terms to the right

-11x=-44

x=-44/-11

x=+4

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