21-x(2x+1)+2(x-4)(x+2)=0

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Solution for 21-x(2x+1)+2(x-4)(x+2)=0 equation: 



21-x(2x+1)+2(x-4)(x+2)=0

We multiply parentheses

-2x^2-x+2(x-4)(x+2)+21=0

We multiply parentheses ..

-2x^2+2(+x^2+2x-4x-8)-x+21=0

We add all the numbers together, and all the variables

-2x^2+2(+x^2+2x-4x-8)-1x+21=0

We multiply parentheses

-2x^2+2x^2+4x-8x-1x-16+21=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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