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21/(4+2x)=x
We move all terms to the left:
21/(4+2x)-(x)=0
Domain of the equation: (4+2x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=-4
x!=-4/2
x!=-2
x∈R
21/(2x+4)-x=0
We add all the numbers together, and all the variables
-1x+21/(2x+4)=0
We multiply all the terms by the denominator
-1x*(2x+4)+21=0
We multiply parentheses
-2x^2-4x+21=0
a = -2; b = -4; c = +21;
Δ = b2-4ac
Δ = -42-4·(-2)·21
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{46}}{2*-2}=\frac{4-2\sqrt{46}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{46}}{2*-2}=\frac{4+2\sqrt{46}}{-4} $
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