21/2(5+c)=48

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Solution for 21/2(5+c)=48 equation: 



21/2(5+c)=48

We move all terms to the left:

21/2(5+c)-(48)=0



Domain of the equation: 2(5+c)!=0

c∈R



We add all the numbers together, and all the variables

21/2(c+5)-48=0

We multiply all the terms by the denominator


-48*2(c+5)+21=0

Wy multiply elements

-96c(c+21=0

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