21/28=(5x+2)/7x

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Solution for 21/28=(5x+2)/7x equation: 



21/28=(5x+2)/7x

We move all terms to the left:

21/28-((5x+2)/7x)=0



Domain of the equation: 7x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(-((5x+2)*28)/7x*28)+147x/7x*28)=0



We calculate terms in parentheses: +(-((5x+2)*28)/7x*28), so:

-((5x+2)*28)/7x*28

We multiply all the terms by the denominator


-((5x+2)*28)



We calculate terms in parentheses: -((5x+2)*28), so:

(5x+2)*28

We multiply parentheses

140x+56

Back to the equation:

-(140x+56)



We get rid of parentheses

-140x-56

Back to the equation:

+(-140x-56)



We get rid of parentheses

-140x+147x/7x*28)-56=0

We multiply all the terms by the denominator


-140x*7x*28)-56+147x=0

Wy multiply elements

-27440x^3*2=0

We do not support expression: x^3

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