21/2b-11=11/2b+12b=b

Solution for 21/2b-11=11/2b+12b=b equation:

21/2b-11=11/2b+12b=b

We move all terms to the left:

21/2b-11-(11/2b+12b)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



Domain of the equation: 2b+12b)!=0

b∈R


We add all the numbers together, and all the variables

21/2b-(+12b+11/2b)-11=0

We get rid of parentheses

21/2b-12b-11/2b-11=0

We multiply all the terms by the denominator


-12b*2b-11*2b+21-11=0

We add all the numbers together, and all the variables

-12b*2b-11*2b+10=0

Wy multiply elements

-24b^2-22b+10=0

a = -24; b = -22; c = +10;
Δ = b2-4ac
Δ = -222-4·(-24)·10
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-38}{2*-24}=\frac{-16}{-48}
=1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+38}{2*-24}=\frac{60}{-48}
=-1+1/4
$