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21/2x+2=x
We move all terms to the left:
21/2x+2-(x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-1x+21/2x+2=0
We multiply all the terms by the denominator
-1x*2x+2*2x+21=0
Wy multiply elements
-2x^2+4x+21=0
a = -2; b = 4; c = +21;
Δ = b2-4ac
Δ = 42-4·(-2)·21
Δ = 184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{184}=\sqrt{4*46}=\sqrt{4}*\sqrt{46}=2\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{46}}{2*-2}=\frac{-4-2\sqrt{46}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{46}}{2*-2}=\frac{-4+2\sqrt{46}}{-4} $
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