21/4(4y-8)+3y+7=(y+1)+5y

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Solution for 21/4(4y-8)+3y+7=(y+1)+5y equation: 



21/4(4y-8)+3y+7=(y+1)+5y

We move all terms to the left:

21/4(4y-8)+3y+7-((y+1)+5y)=0



Domain of the equation: 4(4y-8)!=0

y∈R



We add all the numbers together, and all the variables

3y+21/4(4y-8)-((y+1)+5y)+7=0

We multiply all the terms by the denominator


3y*4(4y-8)-(((y+1)+5y))*4(4y-8)+7*4(4y-8)+21=0



We calculate terms in parentheses: -(((y+1)+5y))*4(4y-8), so:

((y+1)+5y))*4(4y-8



Wy multiply elements

12y^2(4-(((y+1)+5y))*4(4y-8)+28y(4+21=0

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