21/5x-5=2(12/5x+3

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Solution for 21/5x-5=2(12/5x+3 equation: 



21/5x-5=2(12/5x+3

We move all terms to the left:

21/5x-5-(2(12/5x+3)=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R





Domain of the equation: 5x+3)-5!=0

x∈R



We calculate fractions


105x/25x^2+(-(2(12*5x)/25x^2=0

We add all the numbers together, and all the variables

105x/25x^2+(-(2(+12*5x)/25x^2=0

We multiply all the terms by the denominator


105x+(-(2(+12*5x)=0



We calculate terms in parentheses: +(-(2(+12*5x), so:

-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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-(2(+12*5x





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