21/7+3/7(3x-5)=4

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Solution for 21/7+3/7(3x-5)=4 equation: 



21/7+3/7(3x-5)=4

We move all terms to the left:

21/7+3/7(3x-5)-(4)=0



Domain of the equation: 7(3x-5)!=0

x∈R



determiningTheFunctionDomain
3/7(3x-5)-4+21/7=0

We add all the numbers together, and all the variables

3/7(3x-5)-1=0

We multiply all the terms by the denominator


-1*7(3x-5)+3=0

Wy multiply elements

-7x(3+3=0

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