21/z=3(2)

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Solution for 21/z=3(2) equation: 



21/z=3(2)

We move all terms to the left:

21/z-(3(2))=0



Domain of the equation: z!=0

z∈R



determiningTheFunctionDomain
21/z-32=0

We multiply all the terms by the denominator


-32*z+21=0

We add all the numbers together, and all the variables

-32z+21=0

We move all terms containing z to the left, all other terms to the right

-32z=-21

z=-21/-32

z=21/32

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