210=(5z-3)+(4z)+(4z)+(5z-3)

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Solution for 210=(5z-3)+(4z)+(4z)+(5z-3) equation:



210=(5z-3)+(4z)+(4z)+(5z-3)
We move all terms to the left:
210-((5z-3)+(4z)+(4z)+(5z-3))=0
We calculate terms in parentheses: -((5z-3)+4z+4z+(5z-3)), so:
(5z-3)+4z+4z+(5z-3)
We add all the numbers together, and all the variables
8z+(5z-3)+(5z-3)
We get rid of parentheses
8z+5z+5z-3-3
We add all the numbers together, and all the variables
18z-6
Back to the equation:
-(18z-6)
We get rid of parentheses
-18z+6+210=0
We add all the numbers together, and all the variables
-18z+216=0
We move all terms containing z to the left, all other terms to the right
-18z=-216
z=-216/-18
z=+12

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