210=(5z-3)+(4z)+(4z)+(5z-3)

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Solution for 210=(5z-3)+(4z)+(4z)+(5z-3) equation: 



210=(5z-3)+(4z)+(4z)+(5z-3)

We move all terms to the left:

210-((5z-3)+(4z)+(4z)+(5z-3))=0



We calculate terms in parentheses: -((5z-3)+4z+4z+(5z-3)), so:

(5z-3)+4z+4z+(5z-3)

We add all the numbers together, and all the variables

8z+(5z-3)+(5z-3)

We get rid of parentheses

8z+5z+5z-3-3

We add all the numbers together, and all the variables

18z-6

Back to the equation:

-(18z-6)



We get rid of parentheses

-18z+6+210=0

We add all the numbers together, and all the variables

-18z+216=0

We move all terms containing z to the left, all other terms to the right

-18z=-216

z=-216/-18

z=+12

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