210t-5t2=0

Solution for 210t-5t2=0 equation:

210t-5t^2=0

a = -5; b = 210; c = 0;
Δ = b2-4ac
Δ = 2102-4·(-5)·0
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{44100}=210$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(210)-210}{2*-5}=\frac{-420}{-10}
=+42
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(210)+210}{2*-5}=\frac{0}{-10}
=0
$